C库函数 int ispunct(int c) 检查传递的字符是否是标点符号品格的标点符号是任何图形字符（如isgraph）这是不是字母，数字（isalnum），。

声明

以下是ispunct（）函数的声明。

int ispunct(int c);

参数

• c -- 这是要检查的字符。

返回值

这个函数如果c是一个标点符号一样返回一个非零值（true），否则返回零（false）

例子

下面的例子显示ispunct（）函数的用法。

#include <stdio.h>
#include <ctype.h>

int main()
{
   int var1 = 't';
   int var2 = '1';
   int var3 = '/';
   int var4 = ' ';

   if( ispunct(var1) )
   {
       printf("var1 = |%c| is a punctuation character
", var1 );
   }
   else
   {
       printf("var1 = |%c| is not a punctuation character
", var1 );
   }
   if( ispunct(var2) )
   {
       printf("var2 = |%c| is a punctuation character
", var2 );
   }
   else
   {
       printf("var2 = |%c| is not a punctuation character
", var2 );
   }
   if( ispunct(var3) )
   {
       printf("var3 = |%c| is a punctuation character
", var3 );
   }
   else
   {
       printf("var3 = |%c| is not a punctuation character
", var3 );
   }
   if( ispunct(var4) )
   {
       printf("var4 = |%c| is a punctuation character
", var4 );
   }
   else
   {
       printf("var4 = |%c| is not a punctuation character
", var4 );
   }
   
   return(0);
}   

让我们编译和运行上面的程序，这将产生以下结果：

var1 = |t| is not a punctuation character
var2 = |1| is not a punctuation character
var3 = |/| is a punctuation character
var4 = | | is not a punctuation character

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