在Java中，如何搜索数组中的最小值和最大元素？

此示例显示如何使用Collection类的Collection.max()和Collection.min()方法来搜索数组中的最小和最大元素。

package com.yiibai;

import java.util.Arrays;
import java.util.Collections;

public class ArraySearchMaxMin {
    public static void main(String[] args) {
        int numbers[] = new int[] { 28, 21, 17, 41, 34, 29, 15 };
        int s = numbers[0];
        int l = numbers[0];

        for (int i = 1; i < numbers.length; i++) {
            if (numbers[i] > l)
                l = numbers[i];
            else if (numbers[i] < s)
                s = numbers[i];
        }
        System.out.println("Largest Number is : " + l);
        System.out.println("Smallest Number is : " + s);
    }
}

执行上面示例代码，得到以下结果 -

Largest Number is : 41
Smallest Number is : 15

示例2

数组中最小和最大元素的另一个示例示例。

package com.yiibai;

import java.util.Arrays;
import java.util.Collections;

public class ArraySearchMaxMin2 {
    public static void main(String[] args) {
        Integer[] numbers = { 18, 22, 7, 15, 40, 19, 25 };
        int min = (int) Collections.min(Arrays.asList(numbers));
        int max = (int) Collections.max(Arrays.asList(numbers));

        System.out.println("Min number: " + min);
        System.out.println("Max number: " + max);
    }
}

执行上面示例代码，得到以下结果 -

Largest Number is : 40
Smallest Number is : 7

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