如何通过指针访问数组元素？参考以下代码:

#define __STDC_WANT_LIB_EXT1__ 1
#include <stdio.h>
#include <string.h>

int main(void)
{
    char multiple[] = "a string";
    char *p = multiple;
    for (int i = 0; i < strnlen_s(multiple, sizeof(multiple)); ++i)
        printf("multiple[%d] = %c  *(p+%d) = %c  &multiple[%d] = %p  p+%d = %p\n", i, multiple[i], i, *(p + i), i, &multiple[i], i, p + i);
    system("pause");
    return 0;
}

执行上面示例代码，得到以下结果:

multiple[0] = a  *(p+0) = a  &multiple[0] = 00AFF81C  p+0 = 00AFF81C
multiple[1] =    *(p+1) =    &multiple[1] = 00AFF81D  p+1 = 00AFF81D
multiple[2] = s  *(p+2) = s  &multiple[2] = 00AFF81E  p+2 = 00AFF81E
multiple[3] = t  *(p+3) = t  &multiple[3] = 00AFF81F  p+3 = 00AFF81F
multiple[4] = r  *(p+4) = r  &multiple[4] = 00AFF820  p+4 = 00AFF820
multiple[5] = i  *(p+5) = i  &multiple[5] = 00AFF821  p+5 = 00AFF821
multiple[6] = n  *(p+6) = n  &multiple[6] = 00AFF822  p+6 = 00AFF822
multiple[7] = g  *(p+7) = g  &multiple[7] = 00AFF823  p+7 = 00AFF823

因为p被设置为multiple地址，所以p + n基本上与多个+ n相同。可以看到multiple[n]与*(multiple + n)相同。