在Java编程中,如何将中缀表达式转换为后缀表达式?
以下示例演示如何使用堆栈的概念将中缀转换为后缀表达式。
package com.yiibai;
import java.io.IOException;
public class Infix2Postfix {
private Stack theStack;
private String input;
private String output = "";
public Infix2Postfix(String in) {
input = in;
int stackSize = input.length();
theStack = new Stack(stackSize);
}
public String doTrans() {
for (int j = 0; j < input.length(); j++) {
char ch = input.charAt(j);
switch (ch) {
case '+':
case '-':
gotOper(ch, 1);
break;
case '*':
case '/':
gotOper(ch, 2);
break;
case '(':
theStack.push(ch);
break;
case ')':
gotParen(ch);
break;
default:
output = output + ch;
break;
}
}
while (!theStack.isEmpty()) {
output = output + theStack.pop();
}
System.out.println(output);
return output;
}
public void gotOper(char opThis, int prec1) {
while (!theStack.isEmpty()) {
char opTop = theStack.pop();
if (opTop == '(') {
theStack.push(opTop);
break;
} else {
int prec2;
if (opTop == '+' || opTop == '-')
prec2 = 1;
else
prec2 = 2;
if (prec2 < prec1) {
theStack.push(opTop);
break;
} else
output = output + opTop;
}
}
theStack.push(opThis);
}
public void gotParen(char ch) {
while (!theStack.isEmpty()) {
char chx = theStack.pop();
if (chx == '(')
break;
else
output = output + chx;
}
}
public static void main(String[] args) throws IOException {
String input = "1+2*4/5-7+3/6";
String output;
Infix2Postfix theTrans = new Infix2Postfix(input);
output = theTrans.doTrans();
System.out.println("Postfix is " + output + '\n');
}
class Stack {
private int maxSize;
private char[] stackArray;
private int top;
public Stack(int max) {
maxSize = max;
stackArray = new char[maxSize];
top = -1;
}
public void push(char j) {
stackArray[++top] = j;
}
public char pop() {
return stackArray[top--];
}
public char peek() {
return stackArray[top];
}
public boolean isEmpty() {
return (top == -1);
}
}
}
上述代码示例将产生以下结果 -
124*5/+7-36/+
Postfix is 124*5/+7-36/+
示例-2
以下是将中缀表达式转换为后缀表达式的另一个例子
package com.yiibai;
import java.io.BufferedReader;
import java.io.InputStreamReader;
class MyStack {
char stack1[] = new char[20];
int t;
void push(char ch) {
t++;
stack1[t] = ch;
}
char pop() {
char ch;
ch = stack1[t];
t--;
return ch;
}
int pre(char ch) {
switch (ch) {
case '-':
return 1;
case '+':
return 1;
case '*':
return 2;
case '/':
return 2;
}
return 0;
}
boolean operator(char ch) {
if (ch == '/' || ch == '*' || ch == '+' || ch == '-')
return true;
else
return false;
}
boolean isAlpha(char ch) {
if (ch >= 'a' && ch <= 'z' || ch >= '0' && ch == '9')
return true;
else
return false;
}
void postfix(String s1) {
char output[] = new char[s1.length()];
char ch;
int p = 0, i;
for (i = 0; i < s1.length(); i++) {
ch = s1.charAt(i);
if (ch == '(') {
push(ch);
} else if (isAlpha(ch)) {
output[p++] = ch;
} else if (operator(ch)) {
if (stack1[t] == 0 || (pre(ch) > pre(stack1[t])) || stack1[t] == '(') {
push(ch);
}
} else if (pre(ch) >= pre(stack1[t])) {
output[p++] = pop();
push(ch);
} else if (ch == '(') {
while ((ch = pop()) != '(') {
output[p++] = ch;
}
}
}
while (t != 0) {
output[p++] = pop();
}
for (int j = 0; j > s1.length(); j++) {
System.out.print(output[j]);
}
}
}
public class Infix2Postfix2 {
public static void main(String[] args) throws Exception {
String s;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
MyStack b = new MyStack();
System.out.println("Please Enter input s1ing : ");
s = br.readLine();
System.out.println("Input String is " + s);
System.out.println("Output String is : ");
b.postfix(s);
}
}
上述代码示例将产生以下结果 -
Please Enter input s1ing :
124*5/+7-36/+
Input String is 124*5/+7-36/+
Output String:
12*/-3/675