(PHP 5 >= 5.1.0)
array_intersect_key — 使用键名比较计算数组的交集
$array1
, array $array2
[, array $ ...
] )
array_intersect_key() 返回一个数组,该数组包含了所有出现在
array1
中并同时出现在所有其它参数数组中的键名的值。
array1
The array with master keys to check.
array2
An array to compare keys against.
array
A variable list of arrays to compare.
Returns an associative array containing all the entries of
array1
which have keys that are present in all
arguments.
Example #1 array_intersect_key() 例子
<?php
$array1 = array('blue' => 1, 'red' => 2, 'green' => 3, 'purple' => 4);
$array2 = array('green' => 5, 'blue' => 6, 'yellow' => 7, 'cyan' => 8);
var_dump(array_intersect_key($array1, $array2));
?>
以上例程会输出:
array(2) { ["blue"]=> int(1) ["green"]=> int(3) }
上例中可以看到只有 'blue'
和 'green' 两个键名出现在两个数组中,因此被返回。此外注意
'blue' 和 'green'
的值在两个数组中是不同的。但因为只检查键名,因此还是匹配。返回的值只是
array1
中的。
在 key => value 对中的两个键名仅在 (string) $key1 === (string) $key2 时被认为相等。换句话说,执行的是严格类型检查,因此字符串的表达必须完全一样。
vladas dot dirzys at gmail dot com (2012-08-13 08:03:59)
Simple key white-list filter:
<?php
$arr = array('a' => 123, 'b' => 213, 'c' => 321);
$allowed = array('b', 'c');
print_r(array_intersect_key($arr, array_flip($allowed)));
?>
Will return:
Array
(
[b] => 213
[c] => 321
)
pgl at yoyo dot org (2011-07-18 08:01:11)
Note that the order of the keys in the returned array is the same as the order of the keys in the source array. eg:
<?php
$array = array(
'two' => 'a',
'three' => 'b',
'one' => 'c',
);
$keyswant = array(
'one' => '',
'three' => '',
);
print_r(array_intersect_key($array, $keyswant));
?>
Shows:
Array
(
[three] => b
[one] => c
)
chrisbloom7 at gmail dot com (2009-11-11 10:23:06)
Regarding php at keithtylerdotcom solution to emulate
<?php
$z = someFuncReturningAnArray()['some_key'];
?>
His recommended solution will still return an array. To get the value of a single key in an array returned by a function, simply add implode() to the recipe:
<?php
function someFuncReturningAnArray() {
return array(
'a' => 'b',
'c' => 'd',
'e' => 'f',
'g' => 'h',
'i' => 'j'
);
}
//traditional way
$temp = someFuncReturningAnArray();
$b = $temp['a'];
echo print_r($b, 1) . "\n----------\n";
//keithtylerdotcom one-line method
$b = array_intersect_key(someFuncReturningAnArray(), array('a'=>''));
echo print_r($b, 1) . "\n----------\n";
//better one line method
$b = implode('', array_intersect_key(someFuncReturningAnArray(), array('a'=>'')));
echo print_r($b, 1) . "\n----------\n";
?>
markus dot kappe at dix dot at (2009-09-24 04:43:56)
<?php
/**
* calculates intersection of two arrays like array_intersect_key but recursive
*
* @param array/mixed master array
* @param array array that has the keys which should be kept in the master array
* @return array/mixed cleand master array
*/
function myIntersect($master, $mask) {
if (!is_array($master)) { return $master; }
foreach ($master as $k=>$v) {
if (!isset($mask[$k])) { unset ($master[$k]); continue; } // remove value from $master if the key is not present in $mask
if (is_array($mask[$k])) { $master[$k] = $this->myIntersect($master[$k], $mask[$k]); } // recurse when mask is an array
// else simply keep value
}
return $master;
}
?>
pdemaziere at gmail dot com (2009-02-23 07:52:26)
Just a simple script if you want to use one array, which contains only zeros and ones, as mask for another one (both arrays must have the same size of course). $outcome is an array that contains only those values from $source where $mask is equal to 1.
<?php
$outcome = array_values(array_intersect_key( array_values($source), array_filter(array_values($mask)) ));
?>
PS: the array_values() function is necessary to ensure that both arrays have the same numbering/keys, otherwise your masking does not behave as you expect.
Enjoy!
CBWhiz at gmail dot com (2008-01-04 14:04:30)
I have found the following helpful:
<?PHP
function array_merge_default($default, $data) {
$intersect = array_intersect_key($data, $default); //Get data for which a default exists
$diff = array_diff_key($default, $data); //Get defaults which are not present in data
return $diff + $intersect; //Arrays have different keys, return the union of the two
}
?>
It's use is like both of the functions it uses, but keeps defaults and _only_ defaults. It's designed for key arrays, and i'm not sure how it will work on numeric indexed arrays.
Example:
<?PHP
$default = array(
"one" => 1,
"two" => 2
);
$untrusted = array(
"one" => 42,
"three" => 3
);
var_dump(array_merge_default($default, $untrusted));
array(2) {
["two"]=>
int(2)
["one"]=>
int(42)
}
?>
Rod Byrnes (2007-05-05 21:10:42)
Here is a faster version than those shown below, with optimisation for the case when only two arrays are passed. In my tests with a 10000 item first array and a 5000 item second array (run 20 times) this function ran in 1.89 seconds compared with 2.66 for the version posted by dak. For a three array case, same as above but with the third array containing 3333 values, the timing is 3.25 for this version compared with 3.7 for dak's version.
<?php
if (!function_exists('array_intersect_key'))
{
function array_intersect_key($isec, $keys)
{
$argc = func_num_args();
if ($argc > 2)
{
for ($i = 1; !empty($isec) && $i < $argc; $i++)
{
$arr = func_get_arg($i);
foreach (array_keys($isec) as $key)
{
if (!isset($arr[$key]))
{
unset($isec[$key]);
}
}
}
return $isec;
}
else
{
$res = array();
foreach (array_keys($isec) as $key)
{
if (isset($keys[$key]))
{
$res[$key] = $isec[$key];
}
}
return $res;
}
}
}
?>
(2006-07-17 05:31:26)
Here it is a more obvious way to implement the function:
if (!function_exists('array_intersect_key')) {
function array_intersect_key()
{
$arrs = func_get_args();
$result = array_shift($arrs);
foreach ($arrs as $array) {
foreach ($result as $key => $v) {
if (!array_key_exists($key, $array)) {
unset($result[$key]);
}
}
}
return $result;
}
}
Anton Backer (2006-03-30 23:49:50)
Jesse: no, array_intersect_key does not accomplish the same thing as what you posted:
array_flip (array_intersect (array_flip ($a), array_flip ($b)))
because when the array is flipped, values become keys. having duplicate values is not a problem, but having duplicate keys is. array_flip resolves it by keeping only one of the duplicates and discarding the rest. by the time you start intersecting, you've already lost information.
dak (2006-01-23 20:31:45)
A more efficient (and, I think, simpler) compatibility implementation:
<?php
if (!function_exists('array_intersect_key'))
{
function array_intersect_key ($isec, $arr2)
{
$argc = func_num_args();
for ($i = 1; !empty($isec) && $i < $argc; $i++)
{
$arr = func_get_arg($i);
foreach ($isec as $k =>& $v)
if (!isset($arr[$k]))
unset($isec[$k]);
}
return $isec;
}
}
?>
Silvio Ginter (2005-09-23 05:17:28)
Based on the code posted by gaylord dot aulke at 100days.de
i wrote this one. This should implement this function in all versions equal or greater than PHP 4.0
function array_intersect_key($arr1, $arr2) {
$res = array();
foreach($arr1 as $key=>$value) {
$push = true;
for ($i = 1; $i < func_num_args(); $i++) {
$actArray = func_get_arg($i);
if (gettype($actArray) != 'array') return false;
if (!array_key_exists($key, $actArray)) $push = false;
}
if ($push) $res[$key] = $arr1[$key];
}
return $res;
}
gaylord dot aulke at 100days.de (2005-07-04 04:04:02)
I tried to use this function with PHP 5.0.4 under windows but the function does not seem to be implemented.
(Fatal error: Call to undefined function array_intersect_key())
This works as a workaround for 2 arrays at least:
function array_intersect_key($arr1, $arr2) {
$res = array();
foreach($arr1 as $key=>$value) {
if(array_key_exists($key, $arr2)) $res[$key] = $arr1[$key];
}
return $res;
}
aidan at php dot net (2005-05-29 08:51:02)
This functionality is now implemented in the PEAR package PHP_Compat.
More information about using this function without upgrading your version of PHP can be found on the below link:
http://pear.php.net/package/PHP_Compat