(PHP 4, PHP 5)
checkdate — 验证一个格里高里日期
$month
, int $day
, int $year
)检查由参数构成的日期的合法性。如果每个参数都正确定义了则会被认为是有效的。
month
month 的值是从 1 到 12。
day
Day 的值在给定的 month
所应该具有的天数范围之内，闰年已经考虑进去了。
year
year 的值是从 1 到 32767。
如果给出的日期有效则返回 TRUE，否则返回
FALSE。
Example #1 checkdate() 例子
<?php
var_dump(checkdate(12, 31, 2000));
var_dump(checkdate(2, 29, 2001));
?>
以上例程会输出：
bool(true) bool(false)
nisspaATgmail (2013-02-08 12:10:02)
Function to increment date by one day...
<?php
function DateIncrement (&$year, &$month, &$day)
{
if(!checkdate($month, $day, $year)){
if (!checkdate ($month, $day +1, $year)
{
if (!checkdate($month + 1, 1, $year)
{
$month = 1;
$year = $year +1;
$day =1;
return false;
}else
{
$month = $month +1;
$day = 1;
return false;
}
} else {
$day = $day + 1;
return false;
}
}else{
return true;
}
}
?>
mohammed dot aas2012 at gmail dot com (2012-11-07 11:23:21)
format should be in array like: array("m","d","y")
<?php
function isValidDate($strDate,$format,$ex) {
$valid = false;
if(is_array($format) && count($format) == 3 && count(explode($ex,$strDate))==3)
{
$date = array_combine($format,explode($ex,$strDate));
if(intval($date['m']) && intval($date['d']) && intval($date['y'])){
$m = $date['m']; $d = $date['d']; $y = $date['y'];
$valid = checkdate($m,$d,$y);
}
}
return $valid;
}
?>
Martin Kuchar (2012-08-25 00:19:20)
It may be also used with strings and also with leading zero:
checkdate("03","08","2012") is TRUE
bharath.kishore.a AT gmail. DOT com (2012-03-07 14:00:13)
Here is another crooked way to check if given data is valid DATETIME or not.
function checkDateTime($data) {
if (date('Y-m-d H:i:s', strtotime($data)) == $data) {
return true;
} else {
return false;
}
}
Anonymous (2012-02-14 11:10:58)
This is a very good function to check if a date format is valid (with regex).
For example:
2012-2-28 = Valid
2012-2-29 = Valid (leap year)
2012-2-30 = Invalid
2012-1-30 = Valid
2012-1-31 = Valid
2012-2-32 = Invalid
Ensure there are no spaces in the preg_match function:
<?php
function Valid_Date_Format($date)
{
$converted=str_replace('/','-',$date);
if(preg_match("/^((((19|20)(([02468][048])|([13579][26]))-02-29))|((20[0-9][0-9])|(19[0-9][0-9]))-((((0[1-9])|
(1[0-2]))-((0[1-9])|(1\d)|(2[0-8])))|((((0[13578])|(1[02]))-31)|(((0[1,3-9])|
(1[0-2]))-(29|30)))))$/",$converted)===1)
{
return TRUE;
}
return FALSE;
}
?>
I don't know where I got the original code from but I've not found anything better.
pradeepkumarprajapati3 at yahoo dot co dot in (2011-12-18 23:23:38)
don't use strtotime() to format inputs to checkdate(). It would give false results.
Eg,
Below function would return true though it should have been false
<?php
$str = '2011-11-31'; //invalid date, november has 30 days only
function isDateValid($str)
{
$stamp = strtotime($str);
if (!is_numeric($stamp))
return FALSE;
//checkdate(month, day, year)
if ( checkdate(date('m', $stamp), date('d', $stamp), date('Y', $stamp)) )
{
return TRUE;
}
return FALSE;
}
?>
The reason is that strtotime() coverts 2011-11-31 to 2011-12-01.
check with date('Y-m-d', strtotime('2011-11-31'))
Anonymous (2009-07-13 12:06:48)
Beware that checkdate can not be used as validation to check if a date is correct.
The example below will return bool(true) which can result that the <script> part is inserted into the database.
<?php
$date = "01-01-1980 <script>alert('test');</script>";
$aDate_parts = preg_split("/[\s-]+/", $date);
var_dump(
checkdate(
$aDate_parts[1], // Month
$aDate_parts[0], // Day
$aDate_parts[2] // Year
)
);
?>
iamcanadian1973 at gmail dot com (2009-04-16 21:37:23)
[NOTE BY danbrown AT php DOT net: The author's purpose for this function is to determine whether or not a given string $str is a date using a static algorithm.]
<?php
function is_date( $str )
{
$stamp = strtotime( $str );
if (!is_numeric($stamp))
{
return FALSE;
}
$month = date( 'm', $stamp );
$day = date( 'd', $stamp );
$year = date( 'Y', $stamp );
if (checkdate($month, $day, $year))
{
return TRUE;
}
return FALSE;
}
?>
rfeugenio at gmail dot com (2009-03-26 22:21:19)
<?php
// This is a simple function that will get the last day of the month.
function GetLastDayofMonth($year, $month) {
for ($day=31; $day>=28; $day--) {
if (checkdate($month, $day, $year)) {
return $day;
}
}
}
?>
James Luckhurst (2009-03-22 16:26:44)
<?php
/*
## converts a given date format to another date format returns date if the checked date given is valid; otherwise returns NULL
## $s_date the date in e.g. dd/mm/yyyy
## $s_from, $s_to date formats from to i.e. convertdate('13/04/2009','eng','iso','-'); output: 2009-04-13
## date formats available
## 'eng' = dd/mm/yyyy
## 'usa' = mm/dd/yyyy
## 'iso' = yyyy/mm/dd
## $s_return_delimiter returned delimiter e.g. '-' would return dd-mm-yyyy
*/
function convertdate($s_date,$s_from,$s_to,$s_return_delimiter) {
$s_return_date = '';
$s_from = strtolower($s_from);
$s_to = strtolower($s_to);
$s_date = str_replace(array('\'', '-', '.', ',', ' '), '/', $s_date);
$a_date = explode('/', $s_date);
switch($s_from) {
case 'eng': # dd/mm/yyyy
$day = $a_date[0];
$month = $a_date[1];
$year = $a_date[2];
break;
case 'usa': # mm/dd/yyyy
$month = $a_date[0];
$day = $a_date[1];
$year = $a_date[2];
break;
case 'iso': # yyyy/mm/dd
$year = $a_date[0];
$month = $a_date[1];
$day = $a_date[2];
break;
default: # error message
user_error('function convertdate(string $s_date, string $s_from, string $s_to, string $s_return_delimiter) $s_from not a valid type of \'eng\', \'usa\' or \'iso\'');
return NULL;
}
# substitution fixes of valid alternative human input e.g. 1/12/08
if (strlen($day)==1) { $day='0'.$day; } # day -trailing zero missing
if (strlen($month)==1) { $month='0'.$month; } # month -trailing zero missing
if (strlen($year)==3) { $year=substr(date('Y'),0,strlen(date('Y'))-3).$year; } # year -millennium missing
if (strlen($year)==2) { $year=substr(date('Y'),0,strlen(date('Y'))-2).$year; } # year -century missing
if (strlen($year)==1) { $year=substr(date('Y'),0,strlen(date('Y'))-1).$year; } # year -decade missing
switch($s_to) {
case 'eng': # dd/mm/yyyy
$s_return_date = $day.$s_return_delimiter.$month.$s_return_delimiter.$year;
break;
case 'usa': # mm/dd/yyyy
$s_return_date = $month.$s_return_delimiter.$day.$s_return_delimiter.$year;
break;
case "iso": # yyyy/mm/dd
$s_return_date = $year.$s_return_delimiter.$month.$s_return_delimiter.$day;
break;
default: # error message
user_error('function convertdate(string $s_date, string $s_from, string $s_to, string $s_return_delimiter) $s_to not a valid type of \'eng\', \'usa\' or \'iso\'');
return NULL;
}
# if it's an invalid calendar date e.g. 40/02/2009 or rt/we/garbage
if (!is_numeric($month) || !is_numeric($day) || !is_numeric($year)) {
return NULL;
} elseif (!checkdate($month, $day, $year)) {
return NULL;
}
return $s_return_date;
}
echo convertdate('13/04/2009','eng','iso','-');
?>
ystein M (2009-03-18 05:51:56)
I think there is an error in the function from bmauser below. $regexp is overwritten. Here's another version which also accepts missing zeros and two digits year notation.
This function checks date if matches given format and validity of the date.
<?php
/**
* Checks date if matches given format and validity of the date.
* Examples:
* <code>
* is_date('22.22.2222', 'mm.dd.yyyy'); // returns false
* is_date('11/30/2008', 'mm/dd/yyyy'); // returns true
* is_date('30-01-2008', 'dd-mm-yyyy'); // returns true
* is_date('2008 01 30', 'yyyy mm dd'); // returns true
* </code>
* @param string $value the variable being evaluated.
* @param string $format Format of the date. Any combination of <i>mm<i>, <i>dd<i>, <i>yyyy<i>
* with single character separator between.
*/
function is_valid_date($value, $format = 'dd.mm.yyyy'){
if(strlen($value) >= 6 && strlen($format) == 10){
// find separator. Remove all other characters from $format
$separator_only = str_replace(array('m','d','y'),'', $format);
$separator = $separator_only[0]; // separator is first character
if($separator && strlen($separator_only) == 2){
// make regex
$regexp = str_replace('mm', '(0?[1-9]|1[0-2])', $format);
$regexp = str_replace('dd', '(0?[1-9]|[1-2][0-9]|3[0-1])', $regexp);
$regexp = str_replace('yyyy', '(19|20)?[0-9][0-9]', $regexp);
$regexp = str_replace($separator, "\\" . $separator, $regexp);
if($regexp != $value && preg_match('/'.$regexp.'\z/', $value)){
// check date
$arr=explode($separator,$value);
$day=$arr[0];
$month=$arr[1];
$year=$arr[2];
if(@checkdate($month, $day, $year))
return true;
}
}
}
return false;
}
?>
[NOTE BY danbrown AT php DOT net: Original function was written by (bmauser AT gmail) on 16-DEC-2008.]
sebagr@gmail (2009-03-04 09:20:29)
Here's a nice snippet to check if user input is valid:
<?php
$date_format = 'Y-m-d';
$input = '2009-03-03';
$input = trim($input);
$time = strtotime($input);
$is_valid = date($date_format, $time) == $input;
print "Valid? ".($is_valid ? 'yes' : 'no');
?>
venadder at yahoo dot ca (2009-01-21 22:49:12)
Here is a simple IsDate function, using purely PHP functions( A Check for $Stamp can be added to see if it's a legal Unix timestamp ):
<?php
function IsDate( $Str )
{
$Stamp = strtotime( $Str );
$Month = date( 'm', $Stamp );
$Day = date( 'd', $Stamp );
$Year = date( 'Y', $Stamp );
return checkdate( $Month, $Day, $Year );
}
?>
parris dot varney at gmail dot com (2008-12-10 19:24:40)
I put together an is_date function using checkdate. Works the same as is_numeric.
<?php
public static function is_date($date)
{
$date = str_replace(array('\'', '-', '.', ','), '/', $date);
$date = explode('/', $date);
if( count($date) == 1 // No tokens
and is_numeric($date[0])
and $date[0] < 20991231 and
( checkdate(substr($date[0], 4, 2)
, substr($date[0], 6, 2)
, substr($date[0], 0, 4)))
)
{
return true;
}
if( count($date) == 3
and is_numeric($date[0])
and is_numeric($date[1])
and is_numeric($date[2]) and
( checkdate($date[0], $date[1], $date[2]) //mmddyyyy
or checkdate($date[1], $date[0], $date[2]) //ddmmyyyy
or checkdate($date[1], $date[2], $date[0])) //yyyymmdd
)
{
return true;
}
return false;
}
?>
doob_ at gmx dot de (2008-11-26 08:47:01)
<?php
/*
** check a date
** dd.mm.yyyy || mm/dd/yyyy || dd-mm-yyyy || yyyy-mm-dd
*/
function check_date($date) {
if(strlen($date) == 10) {
$pattern = '/\.|\/|-/i'; // . or / or -
preg_match($pattern, $date, $char);
$array = preg_split($pattern, $date, -1, PREG_SPLIT_NO_EMPTY);
if(strlen($array[2]) == 4) {
// dd.mm.yyyy || dd-mm-yyyy
if($char[0] == "."|| $char[0] == "-") {
$month = $array[1];
$day = $array[0];
$year = $array[2];
}
// mm/dd/yyyy # Common U.S. writing
if($char[0] == "/") {
$month = $array[0];
$day = $array[1];
$year = $array[2];
}
}
// yyyy-mm-dd # iso 8601
if(strlen($array[0]) == 4 && $char[0] == "-") {
$month = $array[1];
$day = $array[2];
$year = $array[0];
}
if(checkdate($month, $day, $year)) { //Validate Gregorian date
return TRUE;
} else {
return FALSE;
}
}else {
return FALSE; // more or less 10 chars
}
}
check_date('21.02.1983');
check_date('21-02-1983');
check_date('02/21/1983'); // Common U.S. writing
check_date('1983-02-21'); // iso 8601
?>
saturn at ax dot com dot tw (2008-08-25 23:06:01)
I wrote a simple function to converter datetime to UNIX timestamp. If the input time with error format, the function will return current timestamp.
<?php
function datetime2timestamp($datetime)
{
$datetime = str_replace('-', ' ', $datetime);
$datetime = str_replace('/', ' ', $datetime);
$datetime = str_replace(':', ' ', $datetime);
$array = explode(' ', $datetime);
$year = $array[0];
$month = $array[1];
$day = $array[2];
$array[3] ? $hour = $array[3] : $hour = '00';
$array[4] ? $minute = $array[4] : $minute = '00';
$array[5] ? $second = $array[5] : $second = '00';
if (preg_match("/^(\d{4}) (\d{2}) (\d{2}) ([01][0-9]|2[0-3]) ([0-5][0-9]) ([0-5][0-9])$/", "$year $month $day $hour $minute $second", $matches)) {
if (checkdate($matches[2], $matches[3], $matches[1])) {
return mktime(intval($hour), intval($minute), intval($second), intval($month), intval($day), intval($year));
} else {
return time();
}
} else {
return time();
}
}
?>
el dot vartauy__ at t__gmail dot com (2008-02-29 10:18:41)
for funny leap year detection:
<?php
function is_leap($year=NULL) {
return checkdate(2, 29, ($year==NULL)? date('Y'):$year); // true if is a leap year
}
?>
wasile_ro[at]yahoo[dot]com (2007-10-08 07:30:26)
here's a cool function to validate a mysql datetime:
<?php
function isValidDateTime($dateTime)
{
if (preg_match("/^(\d{4})-(\d{2})-(\d{2}) ([01][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$/", $dateTime, $matches)) {
if (checkdate($matches[2], $matches[3], $matches[1])) {
return true;
}
}
return false;
}
?>
jens wittmann (2007-08-28 08:29:22)
for checking the rime use this:
<?php
function checktime($hour, $minute) {
if ($hour > -1 && $hour < 24 && $minute > -1 && $minute < 60) {
return true;
}
}
?>
brenig code (2007-08-14 11:21:45)
<?php
/**
* check a date combo of the 2
*/
function checkData($date)
{
if (!isset($date) || $date=="")
{
return false;
}
list($dd,$mm,$yy)=explode("/",$date);
if ($dd!="" && $mm!="" && $yy!="")
{
if (is_numeric($yy) && is_numeric($mm) && is_numeric($dd))
{
return checkdate($mm,$dd,$yy);
}
}
return false;
}
?>
a34 at yahoo dot com (2007-07-09 05:21:57)
checkData function posted below does not consider a date entered such as 03/27c/2000. The c will cause it to crash. Here is the fix.
<?php
function checkData($mydate) {
list($yy,$mm,$dd)=explode("-",$mydate);
if (is_numeric($yy) && is_numeric($mm) && is_numeric($dd))
{
return checkdate($mm,$dd,$yy);
}
return false;
}
?>
manuel84**at**mp4**dot**it (2006-12-04 07:49:44)
If you have a date like this gg/mm/aaaa and you'd like to verify that it is in the Italian Format you can use a function like this.
For other date format you can take this code and simply modify the list and explode line
<?php
/**
* check a date in the Italian format
*/
function checkData($date)
{
if (!isset($date) || $date=="")
{
return false;
}
list($dd,$mm,$yy)=explode("/",$date);
if ($dd!="" && $mm!="" && $yy!="")
{
return checkdate($mm,$dd,$yy);
}
return false;
}
?>