Ctype 函数
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ctype_punct

(PHP 4 >= 4.0.4, PHP 5)

ctype_punct Check for any printable character which is not whitespace or an alphanumeric character

说明

bool ctype_punct ( string $text )

Checks if all of the characters in the provided string, text, are punctuation character.

参数

text

The tested string.

返回值

Returns TRUE if every character in text is printable, but neither letter, digit or blank, FALSE otherwise.

范例

Example #1 A ctype_punct() example

<?php
$strings 
= array('ABasdk!@!$#''!@ # $''*&$()');
foreach (
$strings as $testcase) {
    if (
ctype_punct($testcase)) {
        echo 
"The string $testcase consists of all punctuation.\n";
    } else {
        echo 
"The string $testcase does not consist of all punctuation.\n";
    }
}
?>

以上例程会输出:

The string ABasdk!@!$# does not consist of all punctuation.
The string !@ # $ does not consist of all punctuation.
The string *&$() consists of all punctuation.

注释

Note:

如果给出一个 -128 到 255 之间(含)的整数, 将会被解释为该值对应的ASCII字符 (负值将加上 256 以支持扩展ASCII字符). 其它整数将会被解释为该值对应的十进制字符串.

参见


Ctype 函数
在线手册:中文  英文
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