(PHP 5)
date_sunrise — 返回给定的日期与地点的日出时间
$timestamp
[, int $format = SUNFUNCS_RET_STRING
[, float $latitude = ini_get("date.default_latitude")
[, float $longitude = ini_get("date.default_longitude")
[, float $zenith = ini_get("date.sunrise_zenith")
[, float $gmt_offset = 0
]]]]] )
date_sunrise() 返回给定的日期（以
timestamp 指定）与地点的日出时间。
timestamp
取 timestamp所在日期的日出时间。
format
| 常量 | 说明 | 取值举例 |
|---|---|---|
| SUNFUNCS_RET_STRING | 以 string 格式返回结果 | 16:46 |
| SUNFUNCS_RET_DOUBLE | 以 float 格式返回结果 | 16.78243132 |
| SUNFUNCS_RET_TIMESTAMP | 以 integer 格式（时间戳）返回结果 | 1095034606 |
latitude
默认是指北纬。因此如果要指定南纬，必须传递一个负值。 参见 date.default_latitude。
longitude
默认是指东经。因此如果要指定西经，必须传递一个负值。 参见 date.default_longitude。
zenith
默认： date.sunrise_zenith。
gmtoffset
单位是小时。
按指定格式 format 返回的日出时间， 或者在失败时返回 FALSE。
在每 次调用日期/时间函数时，如果时区无效则会引发 E_NOTICE 错误，如果使用系统设定值或 TZ
环境变量，则会引发 E_STRICT 或 E_WARNING 消息。参见
date_default_timezone_set()。
| 版本 | 说明 |
|---|---|
| 5.1.0 |
现在发布 |
Example #1 date_sunrise() 例子
<?php
/* 计算葡萄牙里斯本的日出时间
Latitude: 北纬 38.4 度
Longitude: 西经 9 度
Zenith ~= 90
offset: +1 GMT
*/
echo date("D M d Y"). ', sunrise time : ' .date_sunrise(time(), SUNFUNCS_RET_STRING, 38.4, -9, 90, 1);
?>
以上例程的输出类似于：
Mon Dec 20 2004, sunrise time : 08:54
jonathanNO dot kuhnSPAM at gmailNOSPAM dot com (2010-03-29 11:14:54)
After some searching, I finally found a website that can calculate the sun's zenith. Just look up your city's lat/long (remember, west/south are negative even if it doesn't show where you look up the lat/long) and the time of sunrise/sunset and use this site:
http://solardat.uoregon.edu/cgi-bin/SolarPositionCalculator.cgi
You have to enter in the sunrise/sunset times separately, but it works.
San Diego is:
Lat: 32.73
Long: -117.17
Sunrise Z.: 90.7379
Sunset Z.: 90.8880
fingers at 4tfingers dot info (2008-04-25 20:47:37)
Just for those that are as stupid as me
for the settings in php.ini and sunrise/sunset after googling for a while if found this info
;`Zenith' is the angle that the centre of the Sun makes to a line perpendicular to the Earth's surface.
;
; The best Overall figure for zenith is 90+(50/60) degrees for true sunrise/sunset
; Civil twilight 96 degrees - Conventionally used to signify twilight
; Nautical twilight 102 degrees - the point at which the horizon stops being visible at sea.
; Astronical twilight at 108 degrees - the point when Sun stops being a source of any illumination.
;
;date.sunrise_zenith = 90.583333 85.4
;date.sunset_zenith = 90.583333 85.4
djwice at [the same] dot com (2004-12-02 01:41:29)
The way to use this:
<?php
// De Bilt, The Netherlands, weather station #06260
$lat = 52.10; // North
$long = 5.18; // East
$offset = 1; // difference between GMT and local time in hours
$zenith=90+50/60;
echo "<br><p>Sunrise: ".date_sunrise(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
echo "<br>Sunset: ".date_sunset(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
$zenith=96;
echo "<br><p>Civilian Twilight start: ".date_sunrise(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
echo "<br>Civilian Twilight end: ".date_sunset(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
$zenith=102;
echo "<br><p>Nautical Twilight start: ".date_sunrise(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
echo "<br>Nautical Twilight end: ".date_sunset(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
$zenith=108;
echo "<br><p>Astronomical Twilight start: ".date_sunrise(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
echo "<br>Astronomical Twilight end: ".date_sunset(time(), SUNFUNCS_RET_STRING, $lat, $long, $zenith, $offset);
?>
Zenith according to the U.S. Navy's 1990 Almanac for Computers.
Thanks to George King.
More sources about this topic:
http://www.qarlos.free.fr/navegacion/Sextante/formulas.htm
http://williams.best.vwh.net/sunrise_sunset_algorithm.htm
http://www.kevinboone.com/suntimes.html
http://star-www.st-and.ac.uk/~fv/webnotes/chapt12.htm