(PHP 5 >= 5.3.0)
preg_filter — 执行一个正则表达式搜索和替换
$pattern
, mixed $replacement
, mixed $subject
[, int $limit
= -1
[, int &$count
]] )preg_filter()等价于 preg_replace() 除了它仅仅返回(可能经过转化)与目标匹配的结果. 这个函数怎样工作的更详细信息请阅读 preg_replace()文档.
如果subject
是一个数组,返回一个数组,
其他情况返回一个字符串。
如果没有找到匹配或者发生了错误,当subject
是数组
时返回一个空数组,其他情况返回NULL
。
Example #1 比较 preg_filter() 和 preg_replace()的示例
<?php
$subject = array('1', 'a', '2', 'b', '3', 'A', 'B', '4');
$pattern = array('/\d/', '/[a-z]/', '/[1a]/');
$replace = array('A:$0', 'B:$0', 'C:$0');
echo "preg_filter returns\n";
print_r(preg_filter($pattern, $replace, $subject));
echo "preg_replace returns\n";
print_r(preg_replace($pattern, $replace, $subject));
?>
以上例程会输出:
preg_filter returns Array ( [0] => A:C:1 [1] => B:C:a [2] => A:2 [3] => B:b [4] => A:3 [7] => A:4 ) preg_replace returns Array ( [0] => A:C:1 [1] => B:C:a [2] => A:2 [3] => B:b [4] => A:3 [5] => A [6] => B [7] => A:4 )
sajina_99 at hotmail dot de (2011-09-25 07:07:08)
As I had to work with PHP5.2.X and needed preg_filter I wrote a quick and dirty workaround.
<?php
if (!function_exists('preg_filter')) {
function preg_filter($pattern, $replace, $subject, $limit = -1 , &$count = null) {
if(!is_array($subject)) {
$noArray = 1 ;
$subject = array($subject);
}
$preg = preg_replace($pattern, $replace, $subject, $limit, &$count);
$diff = array_diff($preg, $subject);
if($noArray == 1) $diff = implode($diff) ;
return $diff ;
}
}
?>
MrBertie (2010-12-31 02:35:15)
Another way to filter an array, and simply return the matching items: preg_grep!
Eric Naeseth (2010-12-17 18:38:20)
If you want to just filter an array based on a regular expression, without replacing any of the array values, try RegexIterator: http://us3.php.net/manual/en/class.regexiterator.php