(PHP 4 >= 4.1.0, PHP 5)
socket_getsockname — Queries the local side of the given socket which may either result in host/port or in a Unix filesystem path, dependent on its type
$socket
, string &$addr
[, int &$port
] )Note: socket_getsockname() should not be used with
AF_UNIXsockets created with socket_connect(). Only sockets created with socket_accept() or a primary server socket following a call to socket_bind() will return meaningful values.
socket
A valid socket resource created with socket_create() or socket_accept().
addr
If the given socket is of type AF_INET
or AF_INET6, socket_getsockname()
will return the local IP address in appropriate notation (e.g.
127.0.0.1 or fe80::1) in the
address parameter and, if the optional
port parameter is present, also the associated port.
If the given socket is of type AF_UNIX,
socket_getsockname() will return the Unix filesystem
path (e.g. /var/run/daemon.sock) in the
address parameter.
port
If provided, this will hold the associated port.
成功时返回 TRUE， 或者在失败时返回 FALSE。 socket_getsockname() may also return
FALSE if the socket type is not any of AF_INET,
AF_INET6, or AF_UNIX, in which
case the last socket error code is not updated.
not at valid dot com (2007-10-13 12:35:30)
Just a quick note:
I found socket_getsockname() is not IPv6 compatible or may just return some unexpected results?
<?php
Simple Code Example:
$socket = socket_create(AF_INET,SOCK_STREAM,SOL_TCP);
socket_bind($socket,'0.0.0.0',150);
socket_getsockname($socket, $IP, $PORT);
print $IP.":".$PORT."\n";
?>
This does not print $IP 127.0.0.1 or 192.168.1.1 or even 0.0.0.0 ... etc ... like you would expect ... in my case I receive 10.0.0.0 witch is not a valid port on my system using IPv5 and IPv6! Thus you should rely on using the initial values of socket_bind() to get the local address.
Hope this helps...